Given equation of a circle: x^2 – 4x + y^2 + 6y = 12 rewrite it in a standard form. Find its radius and coordinates of its center. Standard Form:_ r:_

Center:_

The standard form is:

(x - h)² + (y - k)² = r², where (h, k) is the center, r is the radius

Convert the given into standard form by completing square:

x² - 4x + y² + 6y = 12x² - 4x + 4 + y² + 6y + 9 = 12 + 4 + 9(x - 2)² + (y + 3)² = 25(x - 2)² + (y + 3)² = 5²The standard form is above.The center is (h, k) = (2, -3)The radius is r = 5

I'm not sure exactly but my best guess would be 1/4