Company A charges a $125 annual fee plus $7 per hour car share fee. Company B charges $110 plus $10 per hour. What is the minimum number of
hours that a car share needs to be used per year to make company A a better
deal?
A. 6
O Ο Ο
B. 5
C. 9
D. 11
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6 hours

Step-by-step explanation:

A: y=125+7x

B: y=110+10x

for A to be a better deal than B, 125+7x<110+10x has to be true

subtract 7x from both sides and subtract 110 from both sides of the inequality: 15<3xdivide by 3: 5<xso x has to be greater than 5, im pretty sure it's 6 hours but it might also be 5 depending on how it's taught for you

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

I’m not sure i’m sorry