Consuelo Butler III
Homework: Practice
Exam 3
Question 22, 12.5.3
Part 1 of 2
HW Score: 10%, 3 of 30 points
Score: 0 of 1
Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of 2.3.
Iz-score 0.10.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
Percentile 53.98 57.9361.79 65.54 69.15 72.57|75.80|78.81 81.59 84.13
Z-score 111 12 1.3
1.4 1.5 1.6 1.7 1.8 1.9 2.0
Percentile 86.43 88.49 90.32 91.92 93.32 94.52 95.54 96.41 97.13 97.72
|z-score
2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3.0
Percentile 98.21 98.61 98.93 99.18 99.38 99.53 99.65 99.74 99.81 99.87
5
..
a. The percentage of data items that lie below the Z-score is
2

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

abby has a greater debt becasue she owea 5 more then alan does

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.