What is the vertex of the parabola generated by the function f (x) = 2x^2 - 4x + 3 ?

VERTEX: (1,1)     Directrix: Y=0.88    

Step-by-step explanation:

vertex = (1, 1 )

Step-by-step explanation:

Given the equation of a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -

f(x) = 2x² - 4x + 3 ← is in standard form

with a = 2 and b = - 4 , then

= - = 1

Substitute x = 1 into f(x) for corresponding y- coordinate of vertex

f(1) = 2(1)² - 4(1) + 3 = 2 - 4 + 3 = 1

vertex = (1, 1 )

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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