A bag contains 4 white and 2 black balls of the same size and weight and two balls are selected at random without replacement, what are the possible outcomes ?

Step-by-step explanation:

Total balls in bag = 4+2

= 6 balls

Total white balls = 4

Total black balls = 2

The possible outcomes are

Black and Black or White and White or White and Black or Black and White.

Probability of black and black = 2/6

= 1/3

Probability of white and white = 4/6

= 2/3

Probability of Black and white or White and black

= 1/3×2/3

= 2/9

please click thanks and mark brainliest if you like :)

possible outcomes will be white and black, white and white, black and white or black and black

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

d

step-by-step explanation: