You pick a marble from a bag containing 1 green marble, 4 red marbles, 2 yellow marbles, and 3 black marbles. You replace the first marble and then select a second ones find p(blue, then black). If you do not replace the first marble in the previous question before you select the 2nd one, find p(red, then red)

Show your work!!

First question:0

Second question:2/15

Step-by-step explanation:

First:

Total of marbles=10

since there is no blue the probability is 0, since black is 3. then prob= number of black/total number of marbles. =3/10

therefore 0*3/10 =0

second:

probability of red is 4/10

since the first marble wasn't returned,the total number of marbles=9

therefore probability if the second red marble is =3/9 =1/3

probability of first marble *probability of second marble

(4/10)*(1/3) =(4/30)= 2/15

5x+10 is the correct one

hope this

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4