Find the focus and directrix of the parabola y = .5(x + 2)2 – 3​

comparing equation with standard equation x 2 =4aya=2/5co-ordinates of focus =(o,a) i.e. (0, 2/5)equation of directrix=y=-a i.e. y=-(2/5)length of latus rectum= 4a i.e. 8/5co-ordinates of latus rectum=(-2a,a) and (2a,a) i.e. (-4/5,2/5) and (4/5,2/5)..

Step-by-step explanation:

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  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

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