What would your position on the circle (cos q, sin q) be after rotating 72degrees from the point (1,0)? A=(.97, .25)
B=(.31, .95)
C=(.95, .31)
D=(.25, .97)

B=(.31, .95)

Step-by-step explanation:

When your at the point (1,0) you are at 0 degrees (cos 0, sen 0) = (1,0).

So at 72 degrees you moved 72 degrees (cos 72, sin 72) = (.31, .95)

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,