If 4 is a root of x^2- kx+12=0 , then the value of k and the other roots are what?​

k=7

Other root=3

Step-by-step explanation:

If x=4 is a root of the given equation, then it satisfies the given equation.

4^2-k(4)+12=0

We can solve this equation for k.

16-4k+12=0

28-4k=0

28=4k

28/4=k

7=k

So the equation is x^2-7x+12=0

Factor form is (x-3)(x-4)=0 since-3(-4)=12 and -3+-4=-7.

This implies x=3 and x=4 are roots.

45 minutes

step-by-step explanation: