Show that the point (−1,−1,1) lies on both planes. Then find a vector parametric equation for the line of intersection.

YES , Point (-1, -1, 1) lies on plane

Step-by-step explanation:

Given:

Equation of plane;

-4x + 2y - z = 1

3x - 2y + 2z = 1

Prove:

Point (-1, -1, 1) lies on plane

Computation:

In equation 1

-4x + 2y - z = 1

By putting values

-4(-1) + 2(-1) - (1) = 1

4 - 2 - 1 = 1

1 = 1

So,

Point (-1, -1, 1) satisfy plane

In equation 2

3x - 2y + 2z = 1

By putting values

3x - 2y + 2z = 1

3(-1) - 2(-1) + 2(1)

-3 + 2 + 2 = 1

1 = 1

So,

Point (-1, -1, 1) satisfy plane

So,

Point (-1, -1, 1) lies on plane

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the answer is $42.96

step-by-step explanation:

hello umm i don't understand your question can you explain it more pls

step-by-step explanation: