For a certain company, the cost function for producing ~ items is C(20) = 40 x + 250 and the revenue function for selling x items is R(x) = -0.5(x - 80)2 +3,200. The maximum capacity of
the company is 110 items.

the answer to the expression is 83

answer: this is not a question

step-by-step explanation: this is a answer

need more detail

step-by-step explanation:

lele

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368