HELP ASAP A bowl contains 5 pieces of red candy, 6 pieces of green candy, and 11 pieces of blue candy. Two pieces of candy are drawn and then replaced back into the bowl. What is the probability of drawing from the bowl a piece of red and green candy?

Red Candy = 5

Green Candy = 6

Blue Candy = 11

Total Candies = 22

Probability = Possible Outcomes/Total Outcomes

Red + Green = 11

Total outcomes = 22

Probability = 11/22

= 1/2

Must click thanks and mark brainliest

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72