ABCD is a rectangle enclosed in a circle with centre at O and radius of 7cm. AOC is a diameter of the circle. the area of the rectangle is
56 2
. find the height of triangle ADC if the base is AC.

9514 1404 393

  4 cm

Step-by-step explanation:

The area of the triangle is half the area of the rectangle. The base of the triangle is the diameter of the circle, 14 cm. So the height is found from ...

  A = 1/2bh

  (56 cm²)/2 = 1/2(14 cm)h

  h = (28 cm²)/(7 cm) = 4 cm

The height of triangle ADC is 4 cm.

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

you'll just earn points here

step-by-step explanation: