If the density of the wood is 3 pounds per cubic foot and if the weight of the solid is 360 pounds, what is the width, w, in feet, of the solid?
(A) 5.0
(B) 2.5
(C) 2.4
(D) 1.5

The area of the triangular face of the solid is 48 if that helps

The width in feet of the given solid is 1.136

Density is defined as the ratio of the mass per unit volume

Density = Mass/Volume

Given

Weight = 360 pounds

Density = 3 pounds per cubic foot

Get the mass;

Since W = mg

m = W/g

m = 360/2.2

m =163.64  lbm/kg

Get the volume

From the formula;

Volume = Mass/Density

Volume = 163.64 /3

Volume = 54.55 ft³

Next is to get the width

Volume of the triangular prism = Base Area * Width

Base Area = 48ft²

54.55 = 48w

w = 54.55/48

w = 1.136

Hence the width of the solid in feet is 1.136ft

Learn more on how to calculate density here

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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