To solve this system of equations using substitution, what could be substituted in place of x in the second equation? 2y + x = 11
31 - y = -4
a. 2y – 11
b. 11 – 2y
c. 3x + 4
d. y - 4/3

b  11-2y

Step-by-step explanation:

b

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.