An object is launched at 14.7 meters per second from an 88.2 meter tall platform. The equation for the object's height (ℎ)
(
h
)
at time
()
(
t
)
seconds after launch is
ℎ()=−4.92+14.7+88.2
h
(
t
)
=
−
4.9
t
2
+
14.7
t
+
88.2
. Assuming
=0
t
=
0
is when the object is launched and
ℎ=0
h
=
0
is when the object is level with the ground, when does the object strike the ground?

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

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a triangular prism is a 3 dimensional shape composed of triangles and rectangles. it is made from two triangular bases and three rectangular sides.  

ur right ive taken the test

step-by-step explanation: