A changes 16. By accident, 6 burned out bulbs have been mixed in with 16 good ones, Ken is replacing old bulbs in his house. If he selects two bulbs at random from the box of 22, what is the
probability they both work?

8/11

Step-by-step explanation:

This is because there are a total of 22 bulbs. 16 of those bulbs work, giving us the fraction: 16/22. If you simplify 16/22 by dividing the numerator and denominator by 2, you get 8/11.

Explanation:

There are 16 working bulbs out of 6+16 = 22 bulbs total.

The probability of randomly selecting a working bulb is 16/22

After that first bulb is selected and not put back, the probability of randomly selecting another working bulb is 15/21. Take note that I subtracted 1 from each part of the original fraction.

So we get the answer of

(16/22)*(15/21) = 240/462 = 40/77 which is choice C.

Extra info:

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

a

step-by-step explanation: