16. How many different words can be formed with the letters of the word 'RAJARAM'? In how many of these,
(i) have two R and J always together?
(ii) being with Rand end with J?

The word "ARRANGE" can be arranged in

2!×2!

7!

=

4

5040

=1260 ways.

For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.

Then the number of ways =

2!

6!

=360.

The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.

Also in the same way, the number of ways where two "A's" are together is 360.

The number of ways where two "A's" and two "R's" are together is 5!=120.

The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.

Step-by-step explanation:

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

a

step-by-step explanation: