You need to test a claim that more than 18% of students at your campus do not know their blood types. Which sampling method would you use? Where would you collect the sample? Describe how you plan to use the chosen sampling method to collect the data.

Given that:

---- i.e. the proportions that do not know their blood group

There are several sampling methods, however the best sampling method to use in this case is a simple random sampling.

This is because it gives each student in the campus an equal chance of being selected to participate.

The sample would be collected from the population of students in the school campus.

From the question, given proportion is about the students in the campus. So, the sample to be selected must represent the case study, which are the students

The chosen sample would be used by conducting a test of hypothesis

To carry out this test, we need to set the null and alternate hypotheses.

Then calculate the critical value.

Then the test statistic.

How the test statistic compares to the critical value will determine if the null hypothesis will be accepted or rejected

Further reading about testing hypothesis:

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.