Find the equation of the line passing through (-4,1) and perpendicular to the line y=x/4+2​

y = -4x

Step-by-step explanation:

First, for an equation of form y=mx+b, m represents the slope. Therefore, for y=x/4+2 = (1/4)*x + 2, 1/4 is the slope. For perpendicular lines, the negative reciprocal of the slope is the slope of the line perpendicular to it. Therefore, the slope of our line is the negative reciprocal of 1/4.

To find the reciprocal of something, we can just divide 1 by it (another way to do this would be to flip the numerator and denominator, so 1/4 turns into 4/1). Therefore, 1/(1/4) = (1/1)/(1/4) = (1/1) * (4/1) = 4. The negative reciprocal is thus -4.

Our equation is therefore of form y = (-4) x + b. To solve for b, we can plug in the point given and solve for b in our equation. We have

-4 = (-4) * 1 + b

-4 = -4 + b

add 4 to both sides to isolate the b

0 = b

Therefore, our equation is

y= (-4)x + 0

y = -4x

no

step-by-step explanation: