If n(A)=36, n(B)=10, n(AU B) = 40 and n(A) = 27 find n(U) and n(AB​

Step-by-step explanation:

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n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

Step-by-step explanation:

ok

56

step-by-step explanation:

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!