Use the grouping method to factor this polynomial. x2 + 2x2 + 12x + 24
O A. (x2 +12)(x+2)
O B. (x2 +6)(x+2)
C. (x² + 2)(x+6)
O D. (x2 + 2)(x+12)

A. (x² + 12)·(x + 2)

Step-by-step explanation:

Question; Factor x³ + 2·x² + 12·x + 24, using the grouping method

The given polynomial is presented as follows;

x³ + 2·x² + 12·x + 24

Using the grouping method, we have;

(x³ + 2·x²)( + 12·x + 24)

Which gives;

x²·(x + 2) + 12·(x + 2)

Therefore, we get;

(x² + 12)·(x + 2)

The correct option is A. (x² + 12)·(x + 2).

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺