A cardboard envelope for a compact disc is a square with an area of 171.61 square centimeters. What are the dimensions of the envelope?

The dimensions of the cardboard envelope are length, 13.1 cm and width, 13.1 cm.

Since the cardboard envelope for a compact disc is a square with an area of 171.61 square centimeters, the area, A of the cardboard envelope = 171.61 cm².

Since the cardboard envelope is a square, its area is A = L² where L = length of side the cardboard envelope = dimension of cardboard envelope.

To find the dimensions of the cardboard envelope, we take the square-root of the area of the cardboard envelope.

Since A = L²

L = √A

substituting the value of A = 171.61 cm² into the equation, we have

L = √A

L = √(171.61 cm²)

L = 13.09 cm

L ≅ 13.1 cm

Since the length of side of the cardboard envelope is 13.1 cm and its is a square, both dimensions are equal. That is, its length and width are equal.

So, the length of the cardboard envelope is 13.1 cm and the width of the cardboard envelope is 13.1 cm

So, the dimensions of the cardboard envelope are length, 13.1 cm and width, 13.1 cm.

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step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

you can't solve x because it is 2 linear equation and you only have one equation