Which of the following pairs of functions are inverses of each other? A. f(x) = 5 + x and g(x) = 5 - x
B. f(x) = 2x -9 and g(x)=x+9/2
C. f(x) = 3-6 and g(x)=x+6/2
D. f(x)= x/3+4 and g(x) = 3x - 4​

Step-by-step explanation:

Rearrange each function to solve for x.

Switch x and y,

The resulting equation is the inverse function.

A:

f(x) = y = 5+x

x = y-5

y = x-5

f⁻¹(x) = x-5

g(x) = 5-x ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

B:

f(x) = y = 2x-9

x = (y+9)/2

y = (x+9)/2

f⁻¹(x) = (x+9)/2

g(x) = (x+9)/2 = f⁻¹(x)

g(x) is the inverse of f(x).

C:

f(x) = y = 2/x - 6

x = 2/(y+6)

y = 2/(x+6)

f⁻¹(x) = 2/(x+6)

g(x) = (x+6)/2 ≠ f⁻¹(x)

D:

f(x) = y = x/3 + 4

x = 3y - 12

y = 3x - 12

f⁻¹(x) = 3x - 12

g(x) = 3x - 4 ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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