For the function f
(
x
)
=
5
(
x
+
10
)
f(x)=5(x+10), find
f
−
1
(
x
)
f
−1
(x).

f
−
1
(
x
)
=
5
x
−
10
f
−1
(x)=5x−10

f
−
1
(
x
)
=
x
5
−
10
f
−1
(x)=
5
x
​
−10

f
−
1
(
x
)
=
x
+
10
5
f
−1
(x)=
5
x+10
​

f
−
1
(
x
)
=
5
(
x
−
10
)
f
−1
(x)=5(x−10)

f-1(x) = x/5 - 10

Step-by-step explanation:

f(x)=5(x+10), f-1(x) = x/5 - 10

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

y=mx+b is the final answer!   : )