n rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=11, what is the area of the shaded region? Write your answer as a decimal, if necessary. Do not include units in your answer.

*see attachment for clearer diagram

16.5

Step-by-step explanation:

BC = 11

AB = 3

Area of the shaded region = area of ∆AEB + area of ∆CED

Area of a triangle is given as,

A = ½*base*height

Find the area of each triangle and add together

✔️Area of ∆AEB = ½*bh

Where,

base (b) = 3

height (h) = ½(BC) = ½(11) = 5.5

Area of ∆AEB = ½*3*5.5 = 8.25

✔️Area of ∆CED = ½*bh

Where,

b = 3

h = ½(BC) = ½(11) = 5.5

Area of ∆CED = ½*3*5.5 = 8.25

✅Area of the shaded region = area of ∆AEB + area of ∆CED

= 8.25 + 8.25

= 16.5

x divided by 8=y

step-by-step explanation:

angle uzt is congruent to angle tzy. angle vzw is congruent to angle yzx.

(credits to leowren)

step-by-step explanation: