Asha found that a vertical line intersects the graph of x = StartAbsoluteValue y EndAbsoluteValue at two points. What can Asha conclude about x = StartAbsoluteValue y EndAbsoluteValue? It is a function of x but not a relation.
It is a relation but not a function of x.
It is both a function of x and a relation.
It is neither a function of x nor a relation.

what can i help u with

Step-by-step explanation:

The graph of x = |y| is as shown in the figure.

When we draw a vertical line, it intersects the graph at two points.

This means for the same value of x , we have two values of y.

Or in other words, for the same pre image, we have two images.

Hence it is not a function.

But for every value of x, we do have a value of y, hence it is a relation.

x = |y| is a relation but it is not a function

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .