Use the diagram (click the image above) to find the measure of the segment or angle. 1. m 2. m 3. GH =
4. BC =

Step-by-step explanation:

From the given angles ∠ABC and ∠GHK,

m∠ABC = m∠GHK [Given]

m∠ABC = m∠GHL + m∠KHL [Since, ∠GHL + ∠KHL = ∠GHK]

(6x + 2)° = (5x - 27)° + (3x + 1)°

6x + 2 = 8x - 26

8x - 6x = 28

2x = 28

x = 14

m(BC) = m(HK) [Given]

3z + 6 = 8z - 9

8z - 3z = 6 + 9

5z = 15

z = 3

m(AB) = m(GH)

5y - 8 = 3y

2y = 8

y = 4

m∠ABC = mGHK = (6x + 2)

                            = 6(14) + 2

                            = 86°

m(AB) = m(GH) = 3y

                        = 3(4)

                        = 12 units

m(BC) = m(HK) = (3z + 6)

                        = 3(3) + 6

                        = 15 units

m(∠KHL) = (3x + 1)°

              = 3(14) + 1

              = 43°

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