A box has 1 red marble, 3 blue marbles, and 4 green marbles. Maya draws a blue marble randomly from the box, replaces it, and then draws another marble randomly. What is the probability of drawing 2 blue marbles in a row? Explain your answer. 12 points to brainliest

9/64

Step-by-step explanation:

So, we need to find the probability of drawing a blue marble the first time. There are a total of 8 marbles, and 3 blue marbles. So, the probability for the FIRST PULL will be:

3/8

Now, you REPLACE it meaning the value will stay the same. So now you just multiply.

3/8 * 3/8 = 9/64

Hope this helps !!

-Ketifa

9/64

Step-by-step explanation:

1 red marble, 3 blue marbles, and 4 green marbles = 8 marbles

1st draw:

P( blue) = blue / total = 3/8

We replace the marble

1 red marble, 3 blue marbles, and 4 green marbles = 8 marbles

2nd draw:

P( blue) = blue / total = 3/8

P(blue, replace, blue) = 3/8 *3/8 = 9/64

the answer is c hope it

step-by-step explanation:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: