Let f(x)=x^2+2 and g(x)=1–3x. Find each function value: 1. (f+g)(-4)
2. (f•g)(-1)
3. g(f(-2))

Step-by-step explanation:

To find (f + g)(-4), we need to evaluate f(-4) and g(-4) and then add those results together:

f(-4) = so

f(-4) = 18

so

g(-4) = 13

18 + 13 = 31; therefore, (f + g)(-4) = 31.

To find (f·g)(-1), we do the same: evaluate f(-1) and g(-1) and multiply those results together.

f(-1) = 3 and

g(-1) = 4 and

3 × 4 = 12; therefore (f·g)(-1) = 12.

To find g(f(-2)), we first evaluate f(-2), then plug that result into the g function.

f(-2) = 6 so

g(6) = -17

answer: the answer is 127 degrees

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2