A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.8 years, and standard deviation of 1.7 years. The 10% of items with the shortest lifespan will last less than how many years?

3.6 years

Step-by-step explanation:

Using the standard normal probability distribution table, we obtain the Zscore which is 10% to left of the distribution.

The Zscore gives, - 1.282

To obtain the number of years, let this be x ;

Recall, the Zscore formula :

Zscore = (x - μ) / σ

x = number of years

μ = 5.8

σ = 1.7

Zscore = (x - μ) / σ

-1.282 = (x - 5.8) / 1.7

-1.282 * 1.7 = x - 5.8

-2.1794 = x - 5.8

-2.1794 + 5.8 = x

x = 3.6206

x = 3.6 years

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

i think the answer is true

step-by-step explanation: