Solve the right triangle, ΔABC, for the missing side and angles to the nearest tenth given sides a = 14.9 and b = 17.5. A. A = 31.6 , B = 58.4 , c = 9.2
B. A = 49.6 , B = 40.4 , c = 23
C. A = 40.4 , B = 49.6 , c = 23
D. A = 40.4 , B = 49.6 , c = 9.2

C. A = 40.4 , B = 49.6 , c = 23

Step-by-step explanation:

First, we need to get the c using the pythagoras theorem;

c² = a²+b²

c² = 14.9²+17.5²

c²  = 222.01 + 306.25

c² = 528.26

c = 22.98

c ≈ 23

Using the sin rule;

a/Sin<A  = c/sin<C

14.9/sin<A = 23/sin90

14.9/sin<A = 23

sin<A = 14.9/23

sin <A = 0.6478

<A = arcsin(0.6478)

<A = 40.4degrees

Also, <A + <B + <C = 180

40.4 + <B + 90 = 180

<B = 180 - 130.4

<B = 49.6degrees

answer

a) the midrange of the data set shown is 85.5

step by step explanation

let's find the midrange.

the midrange is nothing but add the greatest value and the least value, then divide it by 2.

here the greatest value = 99

the least value = 72

midrange = (99 + 72)/2

= 171/2

midrange = 85.5

you.