The position of a particle moving along a coordinate axis is given by s(t) = t^2 - 5t + 1. Find the speed ,velocity and acceleration

speed is 2t - 5

velocity is 2t - 5

a = 2 m/s²

Step-by-step explanation:

Given the position of a particle expressed as:

s(t) = t^2 - 5t + 1

speed v = ds/dt

ds/dt = 2t - 5

Hence the speed is 2t - 5

velocity can also  be expressed as the speed, hence, velocity is 2t - 5

Acceleration is the change in velocity with respect to time. Hence;

a = dv/dt

a = 2 m/s²

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15