Kasonga's TV plan costs $59.99 per month plus $5.49 per first-run movie. How many first-run movies can he watch if he wants to keep his monthly bill to be a maximum of $100?

7

Step-by-step explanation:

We can solve this problem by making an equation for the monthly bill. First, the cost is $59.99 per month, and that cannot be decreased, so we must add all costs to that amount. Next, it costs $5.49 per first run movie, so for each first run movie, we add $5.49 to the total. Therefore, we can write our equation as

59.99 + 5.49 per first run movie = monthly bill

Representing the number of first run movies as r, we can say

59.99 + 5.49 * r = monthly bill

Next, the monthly bill should be less than or equal to 100, so we can say

monthly bill ≤ 100

59.99 + 5.49 * r = monthly bill ≤ 100

Moreover, we want to maximize r, or the amount of first run movies. Because we add money to the monthly bill for each movie, to maximize r, we have to find the maximum money we can spend on the monthly bill that is still less than or equal to 100. To do this, we set the monthly bill to its maximum limit, or 100, so we have

59.99 + 5.49 * r = 100

subtract 59.99 from both sides to isolate the f and its coefficient

40.01 = 5.49 * r

divide both sides by 5.49 to isolate the variable

r ≈ 7.29

Since we can't buy .29 of a movie, and rounding up to 8 movies would cause us to go past 100 dollars, the maximum movies he can watch if he wants to keep his monthly bill ≤ 100  is 7

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.