Using a directrix of y = 5 and a focus of (4, 1), what quadratic function is created?
HELP PLS

(x-4)^2=-8(y-3)

This is a parabola.

Step-by-step explanation:

Since the directrix is horizontal, the parabola faces up or down. Since the focus is below the directix it faces down. This means p will be negative in the equation (x-h)^2=4p(y-k).

p also tells us the half the distance between the focus and the directrix. The distance between 1 and 5 is 4, so p=-2.

The vertex is half way point between focus (4,1) and directrix y=5.

So the vertex is (4, [1+5]/2 )= (4 ,6/2)=(4,3). This is (h,k) in our equation.

(x-h)^2=4p(y-k)

(x-4)^2=4×-2(y-3)

(x-4)^2=-8(y-3)

y -5 = (-1/4)(x + 8)

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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