Larissa is ordering nachos at a restaurant, and the server tells her that she can have up to four toppings: ground beef, black beans, refried beans, and sour cream. Since she cannot decide how many of the toppings she wants, she tells the server to surprise her. If the server randomly chooses which toppings to add, what is the probability that Larissa gets just refried beans and sour cream

0.0625

Step-by-step explanation:

Given that :

Number of toppings = 4 (ground beef, black beans, refried beans, and sour cream)

The probability of choosing any particular topping at random from the four is :

Probability = required / total possible outcomes

Hence, P = 1 / 4 = 0.25

Hence, the probability of choosing : getting refried bean and sour cream :

P(refried bean) = 1/4

P(sour cream) = 1/4

P(refried bean and sour cream) = 1/4 * 1/4 = 1/16 =

0.0625

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

i believe so, according to my "strange" way of figuring out weird math problems like this.