Suppose a deck of cards contains 13 cards: 5 green cards numbered 1-5, 4 red cards numbered 1-4, and 4 blue cards numbered 1-4.
For 3.1-3.3, 5 draws are made without replacement. X is the number of green cards drawn and Y is the number of red cards drawn. Z is the sum of the numbers on the tickets.
G1 = first card is green
G2 = second card is green
Enter the probability as a fraction.
P(at least one green) = .

Step-by-step explanation:

Given

Solving (a):

This is calculated as:

Solving (b):

This is calculated as:

-- this is so because the selection is without replacement

Solving (c):

Using the complement rule, we have:

To calculate , we have:

--- Green

---- Not green

The probability that both selections are not green is:

So, we have:

Simplify

Recall that:

Take LCM

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm