Mathematics, 22.07.2021 16:10 samstuart10p3g96w
A transformation is applied to △JKL to form △J′K′L′ .
△JKL has coordinates J (0, 0), K (6, 0), and L (6, 3).
The image has coordinates J’ (0, 0), K’ (-6, 0), and L’ (-6, 3).
Which transformation was performed on △JKL?
A. A reflection across the x-axis
A. , , A reflection across the x -axis, , ,
B. A reflection across the y-axis
B. , , A reflection across the y -axis, , ,
C. A translation of 1 unit to the right and 1 unit up
C. , , A translation of 1 unit to the right and 1 unit up, , ,
D. A rotation of 180° counterclockwise about the origin
Answers: 2
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Given: ab ≅ cd and ad ≅ bc prove: abcd is a parallelogram. statements reasons 1. ab ≅ cd; ad ≅ bc 1. given 2. ac ≅ ac 2. reflexive property 3. △adc ≅ △cba 3. ? 4. ∠dac ≅ ∠bca; ∠acd ≅ ∠cab 4. cpctc 5. ∠dac and ∠bca are alt. int. ∠s; ∠acd and ∠cab are alt. int. ∠s 5. definition of alternate interior angles 6. ab ∥ cd; ad ∥ bc 6. converse of the alternate interior angles theorem 7. abcd is a parallelogram 7. definition of parallelogram what is the missing reason in step 3? triangle angle sum theorem sas congruency theorem sss congruency theorem cpctc
Answers: 1
Mathematics, 22.06.2019 04:00
1.multiply and simplify if possible. √7x (√x − 7√7) 2. what is the simplest form of the radical expression? 33√2a−63√2a
Answers: 2
A transformation is applied to △JKL to form △J′K′L′ .
△JKL has coordinates J (0, 0), K (6, 0), and...
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