Why is (x^2+2xy+y^2) greater than 2(x+y)
when x and y are over zero and X>Y

Step-by-step explanation:

This is true because if we were to plug in values for x and y the first equation will have a greater value.

Lets try 2 for x and y

2^2+2(2)(2)+2^2                                                                                              

4+8+4

=16

and for the other expression

2(2+2)

4+4

8

And 16 is greater then 8 this is true for all real rational numbers

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184