Can anyone help me with this ?

The correct answer, pertaining to the proposed interrogate, is acknowledged as x = 3.

Step-by-step explanation:

To evaluate for such, a comprehension of linear data must be obtained:

Slope = rise/run, defined as the agglomerate distance between two differentiated points.

X-intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y-intercept: The peculiar point in which linear data is observed to intersect the y-axis.

If there is a vertical line intersecting the x-axis, the particular point (x, y) is identified as what x is equated to.

Likewise, if there is a horizontal line intersecting the y-axis, the particular point (x, y) is identified as what y is equated to.

Thus, the following must be applied to the interrogate:

- Vertical line, thus determine the point in which the data intersects the x-axis.

- Such is identified as (3,0).

Thus, since that is the only linear figure intersecting at such peculiar axis, 3 is the equated value of x.

Hence, x = 3.

*I hope this helps.

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

x = 3 ± √(5+y)