A line segment has one endpoint of A (-3,2) and a slope of (-3/5). Find coordinates for B

Step-by-step explanation:

This is a very interesting problem. We are given the slope and one point, which makes this funner than normal ;)

Filling in the slope formula with what we are given:

which simplifies to

Since slope is rise over run, the rise number is -3; the run number is 5. That means that the equation to find the y coordinate comes from -3 = y - 2; the equation to find the x coordinate comes from 5 = x + 3 (keep in mind that you could have made the x coordinate the negative one; it doesn't matter. You will get the same answer regardless...promise).

Solving for y:

-3 = y - 2 and

y = -1

Solving for x:

5 = x + 3 and

x = 2

Let's check those coordinates in the slope formula and see if our slope is in fact -3/5:

so we're all good!

The coordinates of B are (2, -1)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step :