A baseball stadium has 15,002 seats. The lower level has 50 fewer than three times as many seats as the upper level. The middle level has 40 more than twice as many seats as the upper level. You solved for x and found that the upper level has 2,502 seats.

upper level chairs = 2,502 chairs

Lower level chairs = 7,456 chairs

Middle level chairs = 5044 chairs

Step-by-step explanation:

A baseball stadium holds 15,002 seats. The lower level has 50 fewer than three times as many seats as the upper level. The middle level has 40 more than twice as many seats as the upper level. The upper level has( ) seats.

Total chairs in the stadium = 15,002

Let

upper level chairs = x

Lower level chairs = 3x - 50

Middle level chairs = 2x + 40

Total = lower level + middle level + upper level

15,002 = (3x - 50) + (2x + 40) + x

15,002 = 3x - 50 + 2x + 40 + x

15,002 = 6x - 10

15,002 + 10 = 6x

15,012 = 6x

x = 15,012 / 6

x = 2,502

upper level chairs = x = 2,502 chairs

Lower level chairs = 3x - 50

3(2,502) - 50

= 7506 - 50

= 7,456 chairs

Middle level chairs = 2x + 40

= 2(2502) + 40

= 5004 + 40

= 5044 chairs

sorry i need the points

step-by-step explanation:

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