Find all real and non-real roots of the function ƒ(x) = x2 + 49. Question 1 options: A) x = –7, 7 B) x = –7i, 7i C) x = –49i, 49i D) x = i + 7, i – 7

A

Step-by-step explanation:

f(x) = x²-49 , rewrite it as a difference of two perfect squares

f(x) = x² -7², use the formula a²-b² = (a+b)(a-b)

(x-7)(x+7) = 0, consider f(x) =0 to find the roots

x-7=0, gives x = 7

x+7 =0 gives x = -7

the roots are 7 and -7

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice