Pls help The equation of a line parallel to 6x – 2y + 10 = 0 and passes through the point
(-2,7).

y=3x-1

Step-by-step explanation:

Y = 3X + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

6x - 2y + 10 = 0 ( subtract 6x + 10 from both sides )

- 2y = - 6x - 10 ( divide terms by - 2 )

y = 3x + 5 ← in slope- intercept form

with slope m = 3

Parallel lines have equal slopes , so

y = 3x + c ← is the partial equation

To find c substitute (- 2, 7 ) into the partial equation

7 = - 6 + c ⇒ c = 7 + 6 = 13

y = 3x + 13 ← equation of line in slope- intercept form

is it 35

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.