A is the point (0, 8) and R is the point (5, 6). Find the point Con the y-axis such that angle ABC is 90°​

(0, -13/2) or (0, -6.5)

Step-by-step explanation:

a point on the y-axis means x=0.

so, the solution is a point (0, y).

and I assume (5, 6) is not R but is B.

for the angle at B being 90 degrees, we are looking at a right-angled triangle, and basic Pythagoras has to be true :

c² = a² + b²

with c being the Hypotenuse (the line opposite of the angle with the 90 degrees).

in our case, this c is the connection from A to C.

and a and b are the connections AB and BC.

so,

AC² = AB² + BC²

the distance between two points is again calculated via Pythagoras, where the differences in x and y directions are the sides, and the distance itself is the Hypotenuse.

so, we get

(0-0)² + (8-y)² = (0-5)² + (8-6)² + (5-0)² + (6-y)²

(8-y)² = -5² + 2² + 5² + (6-y)²

64 - 16y + y² = 25 + 4 + 25 + 36 - 12y + y²

64 - 16y + y² = 90 - 12y + y²

64 - 16y = 90 - 12y

-26 = 4y

y = -26/4 = -13/2 = -6.5

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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