An aircraft carrier can travel 450 km in the same time a container ship travels 300 km. If the aircraft carrier was travelling 5 km/h faster what was the speed of the container ship?

10 Km/h

Step-by-step explanation:

Let the speed of the container ship be y

The speed of the aircraft = y + 5

Next, we shall determine the time taken by the aircraft to travel 450 Km. This can be obtained as follow:

Speed of aircraft (Sₐ) = y + 5

Distance travelled (dₐ) = 450 Km

Time for aircraft (tₐ) =?

Speed = distance / time

Sₐ = dₐ / tₐ

y + 5 = 450 / tₐ

Cross multiply

(y + 5) × tₐ = 450

Divide both side by (y + 5)

tₐ = 450 / (y + 5)

Finally, we shall determine the speed of the carrier. This can be obtained as follow:

Speed of container ship (S꜀) = y

Distance travelled (d꜀) = 300 Km

Time for container ship (t꜀) = Time for aircraft (tₐ)

Time for aircraft (tₐ) = 450 / (y + 5)

t꜀ = tₐ

t꜀ = 450 / (y + 5)

Speed = distance / time

S꜀ = d꜀ / t꜀

y = 300 ÷ 450 / (y + 5)

y = 300 × (y + 5) / 450

y = (300y + 1500) / 450

Cross multiply

450y = 300y + 1500

Collect like terms

450y – 300y = 1500

150y = 1500

Divide both side by 150

y = 1500 / 150

y = 10 Km/h

Thus, the speed of the container ship is 10 Km/h.

the answer is: the length is 5/6 yards.

give me a or a 5 star rating if this is correct!

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet