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Mathematics, 19.07.2021 22:50 rubincain698

The work of a student to solve a set of equations is shown: Equation A: y = 15 βˆ’ 2z
Equation B: 2y = 3 βˆ’ 4z

Step 1: βˆ’2(y) = βˆ’2(15 βˆ’ 2z) [Equation A is multiplied by βˆ’2.]
2y = 3 βˆ’ 4z [Equation B]
Step 2: βˆ’2y = 15 βˆ’ 2z [Equation A in Step 1 is simplified.]
2y = 3 βˆ’ 4z [Equation B]
Step 3: 0 = 18 βˆ’ 6z [Equations in Step 2 are added.]
Step 4: 6z = 18
Step 5: z = 3

In which step did the student first make an error?
Step1
Step 2
Step 3
Step 4

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Answers: 1

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The work of a student to solve a set of equations is shown: Equation A: y = 15 βˆ’ 2z
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