What is the equation of the line passing through the points (2, -1) and (5, -10) in slope-intercept form? O y=-3x-5 O y=-3x+5 O Y= 3x-5 O y = 3x + 5​

y= -3x+5

Step-by-step explanation:

firstly find the gradient given by the formula

m=y2-y1/x2-x1

so in this case y2 is -10,x2 is 5,y1 is -1 and x1 is 2

m= -10+1/5-2

m= -9/3

= -3

after finding the gradient use the equation

y-y1=m( x-x1)

y+1= -3(x-2)

y+1= -3x+6

y= -3x+6-1

y= -3x+5

I hope this helps

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the first one

step-by-step explanation:

just id the test.