13 A cylindrical iron rod 8 cm high and 6 cm in diameter stands in a cylindrical tin 12 cm in diameter. See Fig. 15.22. Water is poured into the tin until its depth is 8 cm. How far would the level drop when the rod is removed?​

2cm

Step-by-step explanation:

The volume of water displaced by the rod is

v = πr^2 h = π * 3^2 * 8 = 72π cm^3

The drop in water level is the rod volume divided by the cross-section area of the tin, or

72π/(π*6^2) = 2 cm

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).