Find the area of the quadrilateral.

12cm^2

Step-by-step explanation:

The first thing we want to do is find out what type of quadrilateral is shown so we can identify a formula we can use to solve for the area

The quadrilateral shown is a trapezoid

It's a trapezoid because it has four sides and one pair of parallel sides ( side AD and side BC are both formed vertically making them parallel as they can be extended an infinite length and will never intersect. ) This being the properties of a trapezoid

Now that we have identified the type of quadrilateral that the figure is, let's find the area.

Area of a trapezoid formula:

A = (a+b/2)h

Where a and b = bases and h = height

* Identify variable of quadrilateral shown*

( Note that each unit = 1cm )

The bases have lengths of 4 units (4cm) and 2 units (2cm)

The height can be represented by an imaginary line from a to c

From a to c is 4 units (4cm)

Now that we have identified the variables let's plug them into the formula

A = (a+b/2)h

a = 4

b = 2

h = 4

* Plug the variables into the formula *

A = (4+2)/(2)4

If you plug this into a calculator you get that the area is 12

If you need the work for evaluation here it is:

Evaluate using PEMDAS

Parenthesis

Exponents

Multiplication and Division ( left to right)

Addition and Subtraction ( left to right )

(4+2)/2 * 4

First step is to evaluate the operations inside of the parenthesis (4+2)

6/2 * 4

The next step is to evaluate exponents

There are no exponents so we move on to multiplication and division evaluate whatever come first going left to right

First comes division

3 * 4

Then multiplication

A = 12.

the answer, i believe is y-8=1(x+4)